If $p + q = \sqrt{2}$ (with $p = \sin heta$, $q = \cos heta$, $ heta$ acute), then $ heta = ?$

Question

If $p + q = \sqrt{2}$ (with $p = \sin	heta$, $q = \cos	heta$, $	heta$ acute), then $	heta = ?$

Accepted Answer

$45^\circ$

Answer

$30^\circ$

Answer

$60^\circ$

Answer

$75^\circ$

If p+q=2p + q = \sqrt{2}p+q=2​ (with p=sin⁡θp = \sin\thetap=sinθ, q=cos⁡θq = \cos\thetaq=cosθ, θ\thetaθ acute), then θ=?\theta = ?θ=?