With $\sin heta = p$, $\cos heta = q$, $ an heta = r$ ($ heta$ acute) and $r = \sqrt{3^{-1}}$, then $ heta = ?$

Question

With $\sin	heta = p$, $\cos	heta = q$, $	an	heta = r$ ($	heta$ acute) and $r = \sqrt{3^{-1}}$, then $	heta = ?$

Accepted Answer

$30^\circ$

Answer

$45^\circ$

Answer

$60^\circ$

Answer

$75^\circ$

With sin⁡θ=p\sin\theta = psinθ=p, cos⁡θ=q\cos\theta = qcosθ=q, tan⁡θ=r\tan\theta = rtanθ=r (θ\thetaθ acute) and r=3−1r = \sqrt{3^{-1}}r=3−1​, then θ=?\theta = ?θ=?