$\left(\dfrac{x^p}{x^q}\right)^{p+q-r} \cdot \left(\dfrac{x^q}{x^r}\right)^{q+r-p} \cdot \left(\dfrac{x^r}{x^p}\right)^{

Question

$\left(\dfrac{x^p}{x^q}\right)^{p+q-r} \cdot \left(\dfrac{x^q}{x^r}\right)^{q+r-p} \cdot \left(\dfrac{x^r}{x^p}\right)^{r+p-q} = ?$

Accepted Answer

$1$

Answer

$x$

Answer

$x^{pqr}$

Answer

$0$

(xpxq)p+q−r⋅(xqxr)q+r−p⋅(xrxp)r+p−q=?\left(\dfrac{x^p}{x^q}\right)^{p+q-r} \cdot \left(\dfrac{x^q}{x^r}\right)^{q+r-p} \cdot \left(\dfrac{x^r}{x^p}\right)^{r+p-q} = ?(xqxp​)p+q−r⋅