C-04-Q094mediumsingle_mcqX=(2a−1+3b−1)−1X = (2a^{-1} + 3b^{-1})^{-1}X=(2a−1+3b−1)−1. Then X=?X = ?X=?aab2b+3a\dfrac{ab}{2b + 3a}2b+3aabb2a+3b2a + 3b