C-10-Q048mediumsingle_mcqTherefore the height hhh satisfies—ah=75⋅tan30∘h = 75 \cdot \tan 30^\circh=75⋅tan30∘bh=75tan30∘h = \dfrac{75}{\tan 30^\circ}h=tan30∘75ch=75⋅sin30∘h = 75 \cdot \sin 30^\circh=75⋅sin30∘dh=75cos30∘h = \dfrac{75}{\cos 30^\circ}h=cos30∘75