With $AB$ the height of a tower, $BC=75$ m the horizontal distance, and $\angle ACB = 30^\circ$, the equation $ an 30^\

Question

With $AB$ the height of a tower, $BC=75$ m the horizontal distance, and $\angle ACB = 30^\circ$, the equation $	an 30^\circ$ equals—

Accepted Answer

$\dfrac{AB}{BC}$

Answer

$\dfrac{BC}{AB}$

Answer

$\dfrac{AC}{AB}$

Answer

$\dfrac{AC}{BC}$

With ABABAB the height of a tower, BC=75BC=75BC=75 m the horizontal distance, and ∠ACB=30∘\angle ACB = 30^\circ∠ACB=30∘, the equation tan⁡30∘\tan 30^\circtan30∘ equals—