$AB$ is the common chord of two circles of equal radius. If a line through $B$ meets the two circles at $P$ and $Q$, the

Question

$AB$ is the common chord of two circles of equal radius. If a line through $B$ meets the two circles at $P$ and $Q$, then $	riangle PAQ$ is—

Accepted Answer

isosceles

Answer

right-angled

Answer

equilateral always

Answer

scalene

ABABAB is the common chord of two circles of equal radius. If a line through BBB meets the two circles at PPP and QQQ, then △PAQ\triangle PAQ△PAQ is—