If two chords $AB$ and $CD$ of a circle with centre $O$ meet at an internal point $E$, then $\angle AEC$ equals—

Question

Accepted Answer

$\frac{1}{2}(\angle BOD + \angle AOC)$

Answer

$\angle BOD - \angle AOC$

Answer

$\angle BOD + \angle AOC$

Answer

$\frac{1}{2}(\angle BOD - \angle AOC)$

If two chords ABABAB and CDCDCD of a circle with centre OOO meet at an internal point EEE, then ∠AEC\angle AEC∠AEC equals—