C-11-Q089mediumsingle_mcqIf ax=by=czax = by = czax=by=cz, then x2yz+y2zx+z2xy\dfrac{x^2}{yz} + \dfrac{y^2}{zx} + \dfrac{z^2}{xy}yzx2+z equals—abca2+cab2+abc2\dfrac{bc}{a^2} + \dfrac{ca}{b^2} + \dfrac{ab}{c^2}a2bc+