If $\dfrac{x}{y+z} = \dfrac{y}{z+x} = \dfrac{z}{x+y}$ and $x, y, z$ are not mutually equal, the value of each ratio is—

Question

Accepted Answer

$-1$ or $\dfrac{1}{2}$

Answer

$0$ or $1$

Answer

only $\dfrac{1}{2}$

Answer

$1$ or $-2$

If xy+z=yz+x=zx+y\dfrac{x}{y+z} = \dfrac{y}{z+x} = \dfrac{z}{x+y}y+zx​=z+xy​=x+yz​ and x,y,zx, y, zx,y,z are not mutually equal, the value of each ratio is—