C-09-Q103mediumsingle_mcqIf logay−z=logbz−x=logcx−y\dfrac{\log a}{y - z} = \dfrac{\log b}{z - x} = \dfrac{\log c}{x - y}y−zloga=z−xlogb=x−ylogc, then ax⋅by⋅cza^x \cdot b^y \cdot c^zax⋅by⋅cz equals:a000babcabcabcc111d