If $p = \log_a (bc),\, q = \log_b (ca),\, r = \log_c (ab)$, then $\dfrac{1}{p+1} + \dfrac{1}{q+1} + \dfrac{1}{r+1}$ equa

Question

If $p = \log_a (bc),\, q = \log_b (ca),\, r = \log_c (ab)$, then $\dfrac{1}{p+1} + \dfrac{1}{q+1} + \dfrac{1}{r+1}$ equals:

Accepted Answer

$1$

Answer

$0$

Answer

$-1$

Answer

$abc$

If p=log⁡a(bc), q=log⁡b(ca), r=log⁡c(ab)p = \log_a (bc),\, q = \log_b (ca),\, r = \log_c (ab)p=loga​(bc),q=logb​(ca),r=logc​(ab), then 1p+1+1q+1+1r+1\dfrac{1}{p+1} + \dfrac{1}{q+1} + \dfrac{1}{r+1}p+11​+q+1 equals: