If $a + b + c = 0$, then $\dfrac{1}{x^a + x^{-b} + 1} + \dfrac{1}{x^b + x^{-c} + 1} + \dfrac{1}{x^c + x^{-a} + 1}$ equal

Question

If $a + b + c = 0$, then $\dfrac{1}{x^a + x^{-b} + 1} + \dfrac{1}{x^b + x^{-c} + 1} + \dfrac{1}{x^c + x^{-a} + 1}$ equals:

Accepted Answer

$1$

Answer

$0$

Answer

$-1$

Answer

$x^{a+b+c}$

If a+b+c=0a + b + c = 0a+b+c=0, then 1xa+x−b+1+1xb+x−c+1+1xc+x−a+1\dfrac{1}{x^a + x^{-b} + 1} + \dfrac{1}{x^b + x^{-c} + 1} + \dfrac{1}{x^c + x^{-a} + 1}xa+x−b equals: