C-09-Q074: If $b = 1 + 3^{1/3} + 3^{2/3}$, then $b^3 - 3b^2 - 6b - 4$ equals:

C-09-Q074: If $b = 1 + 3^{1/3} + 3^{2/3}$, then $b^3 - 3b^2 - 6b - 4$ equals: | প্রশ্ন করি

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If b=1+31/3+32/3b = 1 + 3^{1/3} + 3^{2/3}b=1+31/3+32/3, then b3−3b2−6b−4b^3 - 3b^2 - 6b - 4b3−3b2−6b−4 equals: