C-09-Q060mediumsingle_mcqSolving 4x−3⋅2x+2+32=04^x - 3 \cdot 2^{x+2} + 32 = 04x−3⋅2x+2+32=0, the values of xxx are:a1,21, 21,2b2,32, 32,3c3,43, 43,4