C-09-Q059mediumsingle_mcqIf a1/x=b1/y=c1/za^{1/x} = b^{1/y} = c^{1/z}a1/x=b1/y=c1/z and abc=1abc = 1abc=1, then x+y+zx + y + zx+y+z equals:a111b−1-1−1c000d