For a simple pendulum of length $l$ with gravitational acceleration $g$, the time period is

Question

Accepted Answer

$T = 2\pi\sqrt{l/g}$

Answer

$T = 2\pi\sqrt{g/l}$

Answer

$T = \pi\sqrt{l/g}$

Answer

$T = \sqrt{l/g}$

For a simple pendulum of length lll with gravitational acceleration ggg, the time period is