In an optical fiber, $n_{core} = 1.50$ and $n_{clad} = 1.45$. The minimum angle of incidence for total internal reflecti

Question

In an optical fiber, $n_{core} = 1.50$ and $n_{clad} = 1.45$. The minimum angle of incidence for total internal reflection is —

Accepted Answer

75°

Answer

41.8°

Answer

60°

Answer

90°

In an optical fiber, ncore=1.50n_{core} = 1.50ncore​=1.50 and nclad=1.45n_{clad} = 1.45nclad​=1.45. The minimum angle of incidence for total internal reflection is —