C-08-Q093mediumsingle_mcq
Why does a ray incident perpendicularly on a mirror return along the same path?
Why does a ray incident perpendicularly on a mirror return along the same path?
- aangle of incidence is 90°
- bangle of incidence is 0°, so angle of reflection is also 0°; ray coincides with normal
- cmirror absorbs and re-emits
- dray is bent by 90°