C-02-Q077mediumsingle_mcqThe height fallen by a body in time ttt from initial velocity uuu is —ah=ut+12gt2h = ut + \frac{1}{2}gt^2h=ut+21gt2bh=ut−12gt2h = ut - \frac{1}{2}gt^2h=ut−21gt2ch=ut+2gt2h = ut + 2gt^2h=ut+2gt2dh=uth = uth=ut