C-06-Q038mediumsingle_mcqThe relation between Celsius and Fahrenheit temperatures is —aTC=95(TF−32)T_C = \frac{9}{5}(T_F - 32)TC=59(TF−32)bTC=59(TF−32)T_C = \frac{5}{9}(T_F - 32)TC=95(TcTC=59TF+32T_C = \frac{5}{9}T_F + 32TC=95TdTC=TF−273T_C = T_F - 273TC=TF−273