C-09-Q213mediumsingle_mcqIn right △ABC\triangle ABC△ABC with ∠B=90∘\angle B = 90^\circ∠B=90∘, BC=6BC = 6BC=6 and AB=8AB = 8AB=8, then sinA=?\sin A = ?sinA=?a35\dfrac{3}{5}53b45\dfrac{4}{5}