C-09-Q189mediumsingle_mcqSolve: cos2θ−sin2θ=2−5cosθ\cos^2\theta - \sin^2\theta = 2 - 5\cos\thetacos2θ−sin2θ=2−5cosθ, θ\thetaθ acute. θ=?\theta = ?θ=?a30∘30^\circ30∘b45∘45^\circ45∘c60