C-09-Q147mediumsingle_mcqcosec(90∘−θ)=?\operatorname{cosec}(90^\circ - \theta) = ?cosec(90∘−θ)=?asecθ\sec\thetasecθbcosecθ\operatorname{cosec}\thetacosecθctanθ\tan\thetatanθ