With $x, y$ as in the previous question and $\sin heta = \dfrac{x}{y}$, then $\sec heta = ?$

Question

With $x, y$ as in the previous question and $\sin	heta = \dfrac{x}{y}$, then $\sec	heta = ?$

Accepted Answer

$\dfrac{1 + x^2}{1 - x^2}$

Answer

$\dfrac{1 - x^2}{1 + x^2}$

Answer

$1 + x^2$

Answer

$1 - x^2$

With x,yx, yx,y as in the previous question and sin⁡θ=xy\sin\theta = \dfrac{x}{y}sinθ=yx​, then sec⁡θ=?\sec\theta = ?secθ=?