C-02-Q085mediumsingle_mcqA∪B=(A∖B)∪(B∖A)∪(A∩B)A \cup B = (A \setminus B) \cup (B \setminus A) \cup (A \cap B)A∪B=(A∖B)∪(B∖A)∪(A∩B) is a—afalse identitybvalid decomposition of the unioncDe Morgan's lawdcommutative law