C-14-Q160mediumsingle_mcqIn △ABC\triangle ABC△ABC, ADADAD bisects ∠A\angle A∠A, meets BCBCBC at DDD. If AB=7AB = 7AB=7, AC=5AC = 5AC=5, BC=12BC = 12BC=12, then BD=?BD = ?BD=?a555b666c777d