C-14-Q093mediumsingle_mcqWith DE∥BCDE \parallel BCDE∥BC, the area ratio is —a△ABC△ADE=BCDE\dfrac{\triangle ABC}{\triangle ADE} = \dfrac{BC}{DE}△ADE△ABC=DEb△ABC△ADE=BC2DE2\dfrac{\triangle ABC}{\triangle ADE} = \dfrac{BC^{2}}{DE^{2}}△ADE△ABC=c△ABC△ADE=DE2BC2\dfrac{\triangle ABC}{\triangle ADE} = \dfrac{DE^{2}}{BC^{2}}△ADE△ABC=d△ABC△ADE=ADAB\dfrac{\triangle ABC}{\triangle ADE} = \dfrac{AD}{AB}△ADE△ABC=