C-14-Q067: In the proof of Theorem 32, $\triangle APQ \cong \triangle DEF$ by —

C-14-Q067: In the proof of Theorem 32, $\triangle APQ \cong \triangle DEF$ by — | প্রশ্ন করি

In the proof of Theorem 32, △APQ≅△DEF\triangle APQ \cong \triangle DEF△APQ≅△DEF by —