In $ riangle ABC$, $AB = 6$, $AC = 4$, $BC = 10$. $AD$ bisects $\angle A$, meets $BC$ at $D$. Then $BD = ?$

Question

In $	riangle ABC$, $AB = 6$, $AC = 4$, $BC = 10$. $AD$ bisects $\angle A$, meets $BC$ at $D$. Then $BD = ?$

Accepted Answer

$6$

Answer

$4$

Answer

$5$

Answer

$10$

In △ABC\triangle ABC△ABC, AB=6AB = 6AB=6, AC=4AC = 4AC=4, BC=10BC = 10BC=10. ADADAD bisects ∠A\angle A∠A, meets BCBCBC at DDD. Then BD=?BD = ?BD=?