C-14-Q010mediumsingle_mcqComponendo and dividendo together give —aa−ba+b=c+dc−d\dfrac{a-b}{a+b} = \dfrac{c+d}{c-d}a+ba−b=c−dc+dba+ba−b=c+dc−d\dfrac{a+b}{a-b} = \dfrac{c+d}{c-d}a−ba+b=ca+ba−b=c−dc+d\dfrac{a+b}{a-b} = \dfrac{c-d}{c+d}a−ba+b=da+bb=c−dd\dfrac{a+b}{b} = \dfrac{c-d}{d}ba+b=d