C-07-Q049mediumsingle_mcqIn the square construction, AEAEAE is drawn at AAA such that—aAE∥ABAE \parallel ABAE∥ABbAE⊥ABAE \perp ABAE⊥ABc∠EAB=60∘\angle EAB = 60^\circ∠EAB=60∘d∠EAB=45∘\angle EAB = 45^\circ∠EAB=45∘