In a triangle, if $AB AC$ and $AD$ bisects $\angle A$ meeting $BC$ at $D$, then $\angle ADB$ is—

Question

In a triangle, if $AB > AC$ and $AD$ bisects $\angle A$ meeting $BC$ at $D$, then $\angle ADB$ is—

Accepted Answer

obtuse

Answer

acute

Answer

right

Answer

straight

In a triangle, if AB>ACAB > ACAB>AC and ADADAD bisects ∠A\angle A∠A meeting BCBCBC at DDD, then ∠ADB\angle ADB∠ADB is—