$1^{2} + 2^{2} + 3^{2} + \cdots + n^{2} = ?$

Question

Accepted Answer

$\dfrac{n(n+1)(2n+1)}{6}$

Answer

$\dfrac{n(n+1)}{2}$

Answer

$\left[\dfrac{n(n+1)}{2}\right]^{2}$

Answer

$\dfrac{n(n+1)(2n-1)}{6}$

12+22+32+⋯+n2=?1^{2} + 2^{2} + 3^{2} + \cdots + n^{2} = ?12+22+32+⋯+n2=?