C-05-Q102mediumsingle_mcqComparing x2−1=0x^2 - 1 = 0x2−1=0 with ax2+bx+c=0ax^2 + bx + c = 0ax2+bx+c=0, we get—aa=1,b=0,c=−1a = 1, b = 0, c = -1a=1,b=0,c=−1ba=1,b=1,c