Solution set of $\dfrac{1}{x + 2} - \dfrac{1}{x + 5} = \dfrac{1}{x + 3} - \dfrac{1}{x + 4}$ is—

Question

Accepted Answer

empty

Answer

$\{0\}$

Answer

$\{-7/2\}$

Answer

$\{1\}$

Solution set of 1x+2−1x+5=1x+3−1x+4\dfrac{1}{x + 2} - \dfrac{1}{x + 5} = \dfrac{1}{x + 3} - \dfrac{1}{x + 4}x+21​−x+51​=x+31​−x+41​ is—