C-05-Q050mediumsingle_mcqSolution set of x−2x−1−1x−1=2\dfrac{x - 2}{x - 1} - \dfrac{1}{x - 1} = 2x−1x−2−x−11=2 is—a{3}\{3\}{3}b{−3}\{-3\}{−3}c{1}\{1\}{1}