C-05-Q048mediumsingle_mcqSolve 1x+1−1x+4=1x+2−1x+3\dfrac{1}{x + 1} - \dfrac{1}{x + 4} = \dfrac{1}{x + 2} - \dfrac{1}{x + 3}x+11−x+41=x+21−x+31:ax=−52x = -\dfrac{5}{2}x=−25bx=52x = \dfrac{5}{2}