Substituting and solving $\ell\!\left(\dfrac{\sqrt{3}}{2} + 1\right) = 64$ gives $\ell = ?$

Question

Accepted Answer

$\dfrac{128}{2 + \sqrt{3}}$ m

Answer

$\dfrac{64}{\sqrt{3} + 1}$ m

Answer

$32(2 - \sqrt{3})$ m

Answer

$64\sqrt{3}$ m

Substituting and solving ℓ ⁣(32+1)=64\ell\!\left(\dfrac{\sqrt{3}}{2} + 1\right) = 64ℓ(23​​+1)=64 gives ℓ=?\ell = ?ℓ=?