So the broken piece $CD = \dfrac{BD}{\sin 30^\circ} = \dfrac{10}{1/2}$ equals—

C-10-Q083: So the broken piece $CD = \dfrac{BD}{\sin 30^\circ} = \dfrac{10}{1/2}$…

C-10-Q083: So the broken piece $CD = \dfrac{BD}{\sin 30^\circ} = \dfrac{10}{1/2}$… | প্রশ্ন করি

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