In Example 2, with tree $AB=105$ m, foot distance $BC=x$, and $\angle ACB=60^\circ$, $ an 60^\circ$ equals—

Question

In Example 2, with tree $AB=105$ m, foot distance $BC=x$, and $\angle ACB=60^\circ$, $	an 60^\circ$ equals—

Accepted Answer

$\dfrac{AB}{BC}$

Answer

$\dfrac{BC}{AB}$

Answer

$\dfrac{AB}{AC}$

Answer

$\dfrac{BC}{AC}$

In Example 2, with tree AB=105AB=105AB=105 m, foot distance BC=xBC=xBC=x, and ∠ACB=60∘\angle ACB=60^\circ∠ACB=60∘, tan⁡60∘\tan 60^\circtan60∘ equals—