With $\angle BAC = 60^{\circ}$ for tangents $AB,AC$ and centre $O$, $\angle BOC$ equals—

Question

Accepted Answer

$120^{\circ}$

Answer

$300^{\circ}$

Answer

$270^{\circ}$

Answer

$90^{\circ}$

With ∠BAC=60∘\angle BAC = 60^{\circ}∠BAC=60∘ for tangents AB,ACAB,ACAB,AC and centre OOO, ∠BOC\angle BOC∠BOC equals—