If chords $AB,CD$ of a circle with centre $O$ meet at right angles inside the circle, then $\angle AOD + \angle BOC$ equ

Question

If chords $AB,CD$ of a circle with centre $O$ meet at right angles inside the circle, then $\angle AOD + \angle BOC$ equals—

Accepted Answer

two right angles

Answer

one right angle

Answer

three right angles

Answer

four right angles

If chords AB,CDAB,CDAB,CD of a circle with centre OOO meet at right angles inside the circle, then ∠AOD+∠BOC\angle AOD + \angle BOC∠AOD+∠BOC equals—