C-08-Q100mediumsingle_mcqSince ∠BOD=∠BAO+∠ABO=2∠BAO\angle BOD = \angle BAO + \angle ABO = 2\angle BAO∠BOD=∠BAO+∠ABO=2∠BAO, similarly ∠COD\angle COD∠COD equals—a∠CAO\angle CAO∠CAOb2∠CAO2\angle CAO2∠CAOc12∠CAO\frac{1}{2}\angle CAO