C-08-Q062mediumsingle_mcqIn the figure with PQ=xPQ = xPQ=x cm and OR⊥PQOR \perp PQOR⊥PQ, ∠QOS\angle QOS∠QOS equals—a∠POS\angle POS∠POSb∠POQ\angle POQ∠POQc12∠POQ\frac{1}{2}\angle POQ