C-11-Q154mediumsingle_mcqIf a+bb+c=b+cc+a=c+aa+b\dfrac{a+b}{b+c} = \dfrac{b+c}{c+a} = \dfrac{c+a}{a+b}b+ca+b=c+ab+c=a+bc+a and a+b+c≠0a + b + c \ne 0a+b+c=0, then—aa=b=ca = b = ca=b=cba+b+c=0a + b + c = 0a+b+c