The solutions of Example 5, $\dfrac{1 - \sqrt{1+bx}}{1 + \sqrt{1-bx}} \cdot \ldots = 1$ where $0

Question

The solutions of Example 5, $\dfrac{1 - \sqrt{1+bx}}{1 + \sqrt{1-bx}} \cdot \ldots = 1$ where $0 < b < 2a < 2b$, include—

Accepted Answer

$x = 0,\ \pm \dfrac{1}{a}\sqrt{\dfrac{2a}{b} - 1}$

Answer

$x = 0$ only

Answer

$x = 1$ only

Answer

no real root

The solutions of Example 5, 1−1+bx1+1−bx⋅…=1\dfrac{1 - \sqrt{1+bx}}{1 + \sqrt{1-bx}} \cdot \ldots = 11+1−bx​1−1+bx​​⋅…=1 where 0<b<2a<2b0 < b < 2a < 2b0<b<2a<2b, include—