C-11-Q070mediumsingle_mcqIf ab+c=bc+a=ca+b\dfrac{a}{b+c} = \dfrac{b}{c+a} = \dfrac{c}{a+b}b+ca=c+ab=a+bc and a+b+c≠0a+b+c \ne 0a+b+c=0, then by the sum rule each ratio equals—a12\dfrac{1}{2}21b111c