C-11-Q066mediumsingle_mcqIf ab=cd=ef=gh=k\dfrac{a}{b} = \dfrac{c}{d} = \dfrac{e}{f} = \dfrac{g}{h} = kba=dc=fe=hg=k, then a+c+e+gb+d+f+h=\dfrac{a+c+e+g}{b+d+f+h} =b+d+f+ha+c+e+g=a4k4k4kbkkkck4\dfrac{k}{4}4