C-11-Q059mediumsingle_mcqIf ab=cd\dfrac{a}{b} = \dfrac{c}{d}ba=dc, then a2+b2a2−b2\dfrac{a^2+b^2}{a^2-b^2}a2−b2a2+ also equals—ac2−d2c2+d2\dfrac{c^2-d^2}{c^2+d^2}c2+d2c